1+21/100=(1+x/100)^2

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Solution for 1+21/100=(1+x/100)^2 equation: 


x in (-oo:+oo)

21/100+1 = (x/100+1)^2 // - (x/100+1)^2

21/100-(x/100+1)^2+1 = 0

21/100-1*(1/100*x+1)^2+1 = 0

(-1*100*(1/100*x+1)^2)/100+21/100+(1*100)/100 = 0

1*100-1*100*(1/100*x+1)^2+21 = 0

100-1/100*x^2-2*x-79 = 0

21-1/100*x^2-2*x = 0

21-1/100*x^2-2*x = 0

21-1/100*x^2-2*x = 0

DELTA = (-2)^2-(-1/100*4*21)

DELTA = 121/25

DELTA > 0

x = ((121/25)^(1/2)+2)/(-1/100*2) or x = (2-(121/25)^(1/2))/(-1/100*2)

x = -210 or x = 10

(x+210)*(x-10) = 0

((x+210)*(x-10))/100 = 0

((x+210)*(x-10))/100 = 0 // * 100

(x+210)*(x-10) = 0

( x+210 )

x+210 = 0 // - 210

x = -210

( x-10 )

x-10 = 0 // + 10

x = 10

x in { -210, 10 }

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